Q. Write a program to printout following table:
(where num=5)
5*1=5
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5*7=35
5*8=40
5*9=45
5*10=50
Ans.
#include<stdio.h>
#include<conio.h>
int main()
{
int x=1,num,res;
printf("Enter Number : ");
scanf("%d",&num);
while(x<=10)
{
res=num*x;
printf("\n%d*%d=%d",num,x,res);
x++;
}
getch();
return 0;
getch();
return 0;
}
Output of above program :
Enter Number : 5
5*1=5
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5*7=35
5*8=40
5*9=45
5*10=50
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